Files
ComfyUI_frontend/test/subgraph/subgraphUtils.test.ts

148 lines
4.7 KiB
TypeScript

import type { UUID } from "@/utils/uuid"
import { describe, expect, it } from "vitest"
import { LGraph } from "@/litegraph"
import {
findUsedSubgraphIds,
getDirectSubgraphIds,
} from "@/subgraph/subgraphUtils"
import { createTestSubgraph, createTestSubgraphNode } from "./fixtures/subgraphHelpers"
describe("subgraphUtils", () => {
describe("getDirectSubgraphIds", () => {
it("should return empty set for graph with no subgraph nodes", () => {
const graph = new LGraph()
const result = getDirectSubgraphIds(graph)
expect(result.size).toBe(0)
})
it("should find single subgraph node", () => {
const graph = new LGraph()
const subgraph = createTestSubgraph()
const subgraphNode = createTestSubgraphNode(subgraph)
graph.add(subgraphNode)
const result = getDirectSubgraphIds(graph)
expect(result.size).toBe(1)
expect(result.has(subgraph.id)).toBe(true)
})
it("should find multiple unique subgraph nodes", () => {
const graph = new LGraph()
const subgraph1 = createTestSubgraph({ name: "Subgraph 1" })
const subgraph2 = createTestSubgraph({ name: "Subgraph 2" })
const node1 = createTestSubgraphNode(subgraph1)
const node2 = createTestSubgraphNode(subgraph2)
graph.add(node1)
graph.add(node2)
const result = getDirectSubgraphIds(graph)
expect(result.size).toBe(2)
expect(result.has(subgraph1.id)).toBe(true)
expect(result.has(subgraph2.id)).toBe(true)
})
it("should return unique IDs when same subgraph is used multiple times", () => {
const graph = new LGraph()
const subgraph = createTestSubgraph()
const node1 = createTestSubgraphNode(subgraph, { id: 1 })
const node2 = createTestSubgraphNode(subgraph, { id: 2 })
graph.add(node1)
graph.add(node2)
const result = getDirectSubgraphIds(graph)
expect(result.size).toBe(1)
expect(result.has(subgraph.id)).toBe(true)
})
})
describe("findUsedSubgraphIds", () => {
it("should handle graph with no subgraphs", () => {
const graph = new LGraph()
const registry = new Map<UUID, any>()
const result = findUsedSubgraphIds(graph, registry)
expect(result.size).toBe(0)
})
it("should find nested subgraphs", () => {
const rootGraph = new LGraph()
const subgraph1 = createTestSubgraph({ name: "Level 1" })
const subgraph2 = createTestSubgraph({ name: "Level 2" })
// Add subgraph1 node to root
const node1 = createTestSubgraphNode(subgraph1)
rootGraph.add(node1)
// Add subgraph2 node inside subgraph1
const node2 = createTestSubgraphNode(subgraph2)
subgraph1.add(node2)
const registry = new Map<UUID, any>([
[subgraph1.id, subgraph1],
[subgraph2.id, subgraph2],
])
const result = findUsedSubgraphIds(rootGraph, registry)
expect(result.size).toBe(2)
expect(result.has(subgraph1.id)).toBe(true)
expect(result.has(subgraph2.id)).toBe(true)
})
it("should handle circular references without infinite loop", () => {
const rootGraph = new LGraph()
const subgraph1 = createTestSubgraph({ name: "Subgraph 1" })
const subgraph2 = createTestSubgraph({ name: "Subgraph 2" })
// Add subgraph1 to root
const node1 = createTestSubgraphNode(subgraph1)
rootGraph.add(node1)
// Add subgraph2 to subgraph1
const node2 = createTestSubgraphNode(subgraph2)
subgraph1.add(node2)
// Add subgraph1 to subgraph2 (circular reference)
const node3 = createTestSubgraphNode(subgraph1, { id: 3 })
subgraph2.add(node3)
const registry = new Map<UUID, any>([
[subgraph1.id, subgraph1],
[subgraph2.id, subgraph2],
])
const result = findUsedSubgraphIds(rootGraph, registry)
expect(result.size).toBe(2)
expect(result.has(subgraph1.id)).toBe(true)
expect(result.has(subgraph2.id)).toBe(true)
})
it("should handle missing subgraphs in registry gracefully", () => {
const rootGraph = new LGraph()
const subgraph1 = createTestSubgraph({ name: "Subgraph 1" })
const subgraph2 = createTestSubgraph({ name: "Subgraph 2" })
// Add both subgraph nodes
const node1 = createTestSubgraphNode(subgraph1)
const node2 = createTestSubgraphNode(subgraph2)
rootGraph.add(node1)
rootGraph.add(node2)
// Only register subgraph1
const registry = new Map<UUID, any>([[subgraph1.id, subgraph1]])
const result = findUsedSubgraphIds(rootGraph, registry)
expect(result.size).toBe(2)
expect(result.has(subgraph1.id)).toBe(true)
expect(result.has(subgraph2.id)).toBe(true) // Still found, just can't recurse into it
})
})
})